(x+4)^2=(4-x)(4+x)

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Solution for (x+4)^2=(4-x)(4+x) equation: 



(x+4)^2=(4-x)(4+x)

We move all terms to the left:

(x+4)^2-((4-x)(4+x))=0

We add all the numbers together, and all the variables

(x+4)^2-((-1x+4)(x+4))=0

We multiply parentheses ..

-((-1x^2-4x+4x+16))+(x+4)^2=0



We calculate terms in parentheses: -((-1x^2-4x+4x+16)), so:

(-1x^2-4x+4x+16)

We get rid of parentheses

-1x^2-4x+4x+16

We add all the numbers together, and all the variables

-1x^2+16

Back to the equation:

-(-1x^2+16)



We get rid of parentheses

1x^2+(x+4)^2-16=0

We add all the numbers together, and all the variables

x^2+(x+4)^2-16=0

We move all terms containing x to the left, all other terms to the right

x^2+(x+4)^2=16

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